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What are the magnitude and direction of the hawk's velocity relative to the ground?

You are in a hot-air balloon that, relative to the ground, has a velocity of 6.2 m/s in a direction due east. You see a hawk moving directly away from the balloon in a direction due north. The speed of the hawk relative to you is 1.8 m/s. What are the magnitude and direction of the hawk's velocity relative to the ground?

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  1. Assuming that the hawk's direction is relative to the balloon. Then we have a vector sum of (6.2,0) + (0,1.8) = (6.2,1.8). Magnitude = 6.456 m/s, angle = 16.189 deg = 16.189 deg N of E.
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